-29x+8=-6x+7x^2+8

Solution for -29x+8=-6x+7x^2+8 equation:

-29x+8=-6x+7x^2+8

We move all terms to the left:

-29x+8-(-6x+7x^2+8)=0

We get rid of parentheses

-7x^2+6x-29x-8+8=0

We add all the numbers together, and all the variables

-7x^2-23x=0

a = -7; b = -23; c = 0;
Δ = b2-4ac
Δ = -232-4·(-7)·0
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{529}=23$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-23)-23}{2*-7}=\frac{0}{-14}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-23)+23}{2*-7}=\frac{46}{-14}
=-3+2/7
$